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  4. If a graph is plotted between log (a-x) and t, the slope of the straight line is equal to -0.03. The specific reaction rate will be

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Q. If a graph is plotted between $\log (a-x)$ and $t$, the slope of the straight line is equal to $-0.03$. The specific reaction rate will be

Chemical Kinetics

Solution:

Graph of $\log (a-x)$ vs $t$ is a straight line, which shows first order reaction
image
$k=(-2.303) \times(-0.03)$
$=0.069=6.9 \times 10^{-2}$