If a given sample of water contains 0.06 g of Ca2+ ion per kg, calculate the ppm level of Ca2+ ions:

Question

If a given sample of water contains 0.06 g of Ca2+ ion per kg, calculate the ppm level of Ca2+ ions: (A) 0.6 (B) 60 (C) 6 (D) 600

Tardigrade Admin · Accepted Answer

Water contains Ca 2+=0.06 g per kg =0.06 g per 103 g Amount of Ca 2+ ion per 106 g water =(0.06/103) × 106=0.06 × 103=60 g Hence, the ppm level of Ca 2+ ions is 60 .

Q. If a given sample of water contains $0.06 g$ of $C a^{2 +}$ ion per kg, calculate the ppm level of $C a^{2 +}$ ions:

0.6

60

6

600

Water contains $C a^{2 +} = 0.06 g$ per $k g$
$= 0.06 g$ per $103 g$
Amount of $C a^{2 +}$ ion per $106 g$ water
$= \frac{0.06}{1 0 ^{3}} \times 1 0^{6} = 0.06 \times 1 0^{3} = 60 g$
Hence, the ppm level of $C a^{2 +}$ ions is $60$ .

Q. If a given sample of water contains 0.06g of Ca2+ ion per kg, calculate the ppm level of Ca2+ ions:

0.6

60

6

600

Water contains Ca2+=0.06g per kg =0.06g per 103g Amount of Ca2+ ion per 106g water =1030.06​×106=0.06×103=60g Hence, the ppm level of Ca2+ ions is 60 .

Q. If a given sample of water contains $0.06 g$ of $C a^{2 +}$ ion per kg, calculate the ppm level of $C a^{2 +}$ ions:

Water contains $C a^{2 +} = 0.06 g$ per $k g$
$= 0.06 g$ per $103 g$
Amount of $C a^{2 +}$ ion per $106 g$ water
$= \frac{0.06}{1 0 ^{3}} \times 1 0^{6} = 0.06 \times 1 0^{3} = 60 g$
Hence, the ppm level of $C a^{2 +}$ ions is $60$ .