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Q.
If a given sample of water contains $0.06 \,g$ of $ Ca^{2+} $ ion per kg, calculate the ppm level of $ Ca^{2+} $ ions:
J & K CETJ & K CET 2001
Solution:
Water contains $Ca ^{2+}=0.06\, g$ per $kg$
$ =0.06\, g$ per $103 \,g$
Amount of $Ca ^{2+}$ ion per $106 \,g$ water
$=\frac{0.06}{10^{3}} \times 10^{6}=0.06 \times 10^{3}=60 g$
Hence, the ppm level of $Ca ^{2+}$ ions is $60$ .