If a conductor of 3 m in length is moving perpendicularly to magnetic field of 10-4 tesla with the speed of 102 m / s, then the e.m.f. produced across the ends of conductor will be

Question

If a conductor of 3 m in length is moving perpendicularly to magnetic field of 10-4 tesla with the speed of 102 m / s, then the e.m.f. produced across the ends of conductor will be (A) 0.03 volt (B) 0.3 volt (C) 3 × 10-3 volt (D) 3 volt

Tardigrade Admin · Accepted Answer

e=B v l=3 × 10-3 × 102=0.3 volt

Q. If a conductor of $3 m$ in length is moving perpendicularly to magnetic field of $1 0^{- 4}$ tesla with the speed of $1 0^{2} m / s$ , then the e.m.f. produced across the ends of conductor will be

$0.03$ volt

$0.3$ volt

$3 \times 1 0^{- 3}$ volt

$3$ volt

$e = B v l = 3 \times 1 0^{- 3} \times 1 0^{2} = 0.3$ volt

Q. If a conductor of 3m in length is moving perpendicularly to magnetic field of 10−4 tesla with the speed of 102m/s, then the e.m.f. produced across the ends of conductor will be

0.03 volt

0.3 volt

3×10−3 volt

3 volt