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  4. If a conductor of 3 m in length is moving perpendicularly to magnetic field of 10-4 tesla with the speed of 102 m / s, then the e.m.f. produced across the ends of conductor will be

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Q. If a conductor of $3\, m$ in length is moving perpendicularly to magnetic field of $10^{-4}$ tesla with the speed of $10^{2} m / s$, then the e.m.f. produced across the ends of conductor will be

Electromagnetic Induction

Solution:

$e=B v l=3 \times 10^{-3} \times 10^{2}=0.3$ volt