If a bullet of mass 5 gm moving with velocity 100 m /sec, penetrates the wooden block upto 6 cm. Then the average force imposed by the bullet on the block is

Question

If a bullet of mass 5 gm moving with velocity 100 m /sec, penetrates the wooden block upto 6 cm. Then the average force imposed by the bullet on the block is (A) 8300 N (B) 417 N (C) 830 N (D) Zero

Tardigrade Admin · Accepted Answer

u = 100 m/s, u=0, s=0.06 m Retardation =a=(u2/2s) =((100)2/2× 0.06) =(1 × 106/12) ∴ Force =ma=(5× 10-3× 1 × 106/12) =(5000/12) =417 N

Q. If a bullet of mass $5 g m$ moving with velocity $100 m / sec$ , penetrates the wooden block upto $6 c m$ . Then the average force imposed by the bullet on the block is

$8300 N$

$417 N$

$830 N$

Zero

$u = 100 m / s, u = 0, s = 0.06 m$

Retardation $= a = \frac{u ^{2}}{2 s}$

$= \frac{( 100 ) ^{2}}{2 \times 0.06}$

$= \frac{1 \times 1 0 ^{6}}{12}$

$∴$ Force $= ma = \frac{5 \times 1 0 ^{- 3} \times 1 \times 1 0 ^{6}}{12}$

$= \frac{5000}{12}$

$= 417 N$

Q. If a bullet of mass 5gm moving with velocity 100m/sec, penetrates the wooden block upto 6cm. Then the average force imposed by the bullet on the block is

8300N

417N

830N