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  4. If a bullet of mass 5 gm moving with velocity 100 m /sec, penetrates the wooden block upto 6 cm. Then the average force imposed by the bullet on the block is

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Q. If a bullet of mass $5 \,gm$ moving with velocity $100\, m /sec$, penetrates the wooden block upto $6 \,cm$. Then the average force imposed by the bullet on the block is

Laws of Motion

Solution:

$u = 100\, m/s, u=0, s=0.06\,m$
Retardation $=a=\frac{u^{2}}{2s}$
$=\frac{(100)^{2}}{2\times 0.06}$
$=\frac{1 \times 10^{6}}{12}$
$\therefore $ Force $=ma=\frac{5\times 10^{-3}\times 1 \times 10^{6}}{12}$
$=\frac{5000}{12}$
$=417\,N$