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Question
Mathematics
If A=[ beginmatrix 1 2 3 5 endmatrix ], then the value of the determinant |A2009-5A2008| is
Q. If
A
=
[
1
3
2
5
]
,
then the value of the determinant
∣
A
2009
−
5
A
2008
∣
is
5651
205
KEAM
KEAM 2009
Determinants
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A
−
6
27%
B
−
5
21%
C
−
4
22%
D
4
25%
E
6
25%
Solution:
Given,
A
=
[
1
3
2
5
]
⇒
∣
A
∣
=
5
−
6
=
−
1
∴
∣
A
2009
−
5
A
2008
∣
=
∣
A
2008
∣∣
A
−
5
I
∣
=
(
−
1
)
2008
∣
∣
[
1
3
2
5
]
−
[
5
0
0
5
]
∣
∣
=
∣
∣
−
4
3
2
0
∣
∣
=
−
6