If a 6.84% (wt./vol.) solution of cane-sugar (mol. Wt. = 342) is isotonic with 1.52% (wt./vol.) solution of thiocarbamide, then the molecular weight of thiocarbamide is

Question

If a 6.84% (wt./vol.) solution of cane-sugar (mol. Wt. = 342) is isotonic with 1.52% (wt./vol.) solution of thiocarbamide, then the molecular weight of thiocarbamide is (A) 152 (B) 76 (C) 60 (D) 180

Tardigrade Admin · Accepted Answer

C1 = C2 (w1/M1× V1)=(w2/M2× V2) ⇒ (6.84/342×100) =(1.52/M2×100) M2=76

Q. If a 6.84% (wt./vol.) solution of cane-sugar (mol. Wt. = 342) is isotonic with 1.52% (wt./vol.) solution of thiocarbamide, then the molecular weight of thiocarbamide is

$152$

$76$

$60$

$180$

$C_{1} = C_{2}$
$\frac{w _{1}}{M _{1} \times V _{1}} = \frac{w _{2}}{M _{2} \times V _{2}}$
$\Rightarrow \frac{6.84}{342 \times 100}$
$= \frac{1.52}{M _{2} \times 100}$
$M_{2} = 76$