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Q. If a 6.84% (wt./vol.) solution of cane-sugar (mol. Wt. = 342) is isotonic with 1.52% (wt./vol.) solution of thiocarbamide, then the molecular weight of thiocarbamide is

Solutions

Solution:

$C_{1} = C_{2}$
$\frac{w_{1}}{M_{1}\times V_{1}}=\frac{w_{2}}{M_{2}\times V_{2}}$
$\Rightarrow \frac{6.84}{342\times100}$
$=\frac{1.52}{M_{2}\times100}$
$M_{2}=76$