If a 2 m long wire is moving with a velocity of 1 m/s perpendicular to a magnetic field of 0.5 wb/m2, then the emf induced in it, will be:

Question

If a 2 m long wire is moving with a velocity of 1 m/s perpendicular to a magnetic field of 0.5 wb/m2, then the emf induced in it, will be: (A) 2 V (B) 1 V (C) 0.5 V (D) 0.2 V

Tardigrade Admin · Accepted Answer

Here: Length of wire l=2 m Velocity of wire v=1 m text/s Magnetic field B=0.5 wb text/m2 As induced emf E=Bvl=0.5× 1× 2=1 V

Q. If a 2 m long wire is moving with a velocity of 1 m/s perpendicular to a magnetic field of $0.5 w b / m^{2},$ then the emf induced in it, will be:

2 V

1 V

0.5 V

0.2 V

Here: Length of wire $l = 2 m$ Velocity of wire $v = 1 m / s$ Magnetic field $B = 0.5 w b / m^{2}$ As induced emf $E = B v l = 0.5 \times 1 \times 2 = 1 V$

Q. If a 2 m long wire is moving with a velocity of 1 m/s perpendicular to a magnetic field of 0.5wb/m2, then the emf induced in it, will be:

2 V

1 V

0.5 V

0.2 V

Here: Length of wire l=2m Velocity of wire v=1m/s Magnetic field B=0.5wb/m2 As induced emf E=Bvl=0.5×1×2=1V

Q. If a 2 m long wire is moving with a velocity of 1 m/s perpendicular to a magnetic field of $0.5 w b / m^{2},$ then the emf induced in it, will be:

Here: Length of wire $l = 2 m$ Velocity of wire $v = 1 m / s$ Magnetic field $B = 0.5 w b / m^{2}$ As induced emf $E = B v l = 0.5 \times 1 \times 2 = 1 V$