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Q. If a 2 m long wire is moving with a velocity of 1 m/s perpendicular to a magnetic field of $ 0.5\,\,wb/{{m}^{2}}, $ then the emf induced in it, will be:

JIPMERJIPMER 1995

Solution:

Here: Length of wire $ l=2\,m $ Velocity of wire $ v=1\,m\text{/}s $ Magnetic field $ B=0.5\,wb\text{/}{{m}^{2}} $ As induced emf $ E=Bvl=0.5\times 1\times 2=1\,V $