If 96500 C of electricity liberates one gram equivalent of any substance, the time taken for a current of 0.15 A to deposit 20 mg of copper from a solution of copper sulphate is (chemical equivalent of copper = 32).

Question

If 96500 C of electricity liberates one gram equivalent of any substance, the time taken for a current of 0.15 A to deposit 20 mg of copper from a solution of copper sulphate is (chemical equivalent of copper = 32). (A) 5 min 20 s (B) 6 min 42 s (C) 4 min 40 s (D) 5 min 50 s

Tardigrade Admin · Accepted Answer

As Z =(E/F) =(32/96500) According to Faradayâs first law of electrolysis m=ZIt or t =(m/ZI)=(20 ×10-3/(32/ 96500)×0.15)=402 s = 6 min 42 s.

Q. If $96500 C$ of electricity liberates one gram equivalent of any substance, the time taken for a current of $0.15 A$ to deposit 20 mg of copper from a solution of copper sulphate is (chemical equivalent of copper = 32).

5 min 20 s

6 min 42 s

4 min 40 s

5 min 50 s

As $Z = \frac{E}{F} = \frac{32}{96500}$
According to Faraday’s first law of electrolysis
$m = Z I t$
or $t = \frac{m}{Z I} = \frac{20 \times 1 0 ^{- 3}}{( 32/96500 ) \times 0.15} = 402 s$
= 6 min 42 s.

Q. If 96500C of electricity liberates one gram equivalent of any substance, the time taken for a current of 0.15A to deposit 20 mg of copper from a solution of copper sulphate is (chemical equivalent of copper = 32).