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  4. If 96500 C of electricity liberates one gram equivalent of any substance, the time taken for a current of 0.15 A to deposit 20 mg of copper from a solution of copper sulphate is (chemical equivalent of copper = 32).

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Q. If $96500\, C$ of electricity liberates one gram equivalent of any substance, the time taken for a current of $0.15\, A$ to deposit 20 mg of copper from a solution of copper sulphate is (chemical equivalent of copper = 32).

JIPMERJIPMER 2013Current Electricity

Solution:

As $Z =\frac{E}{F} =\frac{32}{96500}$
According to Faraday’s first law of electrolysis
$m=ZIt$
or $t =\frac{m}{ZI}=\frac{20 \times10^{-3}}{\left(32/ 96500\right)\times0.15}=402 s$
= 6 min 42 s.