If 80 g of copper sulphate CuSO 4 ⋅ 5 H 2 O is dissolved in deionised water to make 5 L of solution. The concentration of the copper sulphate solution is x × 10-3 mol L -1. The value of x is [Atomic masses Cu: 63.54 u , S: 32 u , O: 16 u , H: 1 u ]

Question

If 80 g of copper sulphate CuSO 4 ⋅ 5 H 2 O is dissolved in deionised water to make 5 L of solution. The concentration of the copper sulphate solution is x × 10-3 mol L -1. The value of x is [Atomic masses Cu: 63.54 u , S: 32 u , O: 16 u , H: 1 u ] (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Moles of CuSO 4 ⋅ 5 H 2 O =(80/249.54) Molarity =((80/249.54)/5)=64.117 × 10-3 Nearest integer, x=64

Q. If $80 g$ of copper sulphate $C u S O_{4} \cdot 5 H_{2} O$ is dissolved in deionised water to make $5 L$ of solution. The concentration of the copper sulphate solution is $x \times 1 0^{- 3} m o l L^{- 1}$ . The value of $x$ is ____
[Atomic masses $C u : 63.54 u, S : 32 u, O : 16 u, H : 1 u$ ]

Moles of $C u S O_{4} \cdot 5 H_{2} O = \frac{80}{249.54}$
Molarity $= \frac{\frac{80}{249.54}}{5} = 64.117 \times 1 0^{- 3}$
Nearest integer, $x = 64$

Q. If 80g of copper sulphate CuSO4​⋅5H2​O is dissolved in deionised water to make 5L of solution. The concentration of the copper sulphate solution is x×10−3molL−1. The value of x is ____ [Atomic masses Cu:63.54u,S:32u,O:16u,H:1u ]

Moles of CuSO4​⋅5H2​O=249.5480​ Molarity =5249.5480​​=64.117×10−3 Nearest integer, x=64

Q. If $80 g$ of copper sulphate $C u S O_{4} \cdot 5 H_{2} O$ is dissolved in deionised water to make $5 L$ of solution. The concentration of the copper sulphate solution is $x \times 1 0^{- 3} m o l L^{- 1}$ . The value of $x$ is ____
[Atomic masses $C u : 63.54 u, S : 32 u, O : 16 u, H : 1 u$ ]

Moles of $C u S O_{4} \cdot 5 H_{2} O = \frac{80}{249.54}$
Molarity $= \frac{\frac{80}{249.54}}{5} = 64.117 \times 1 0^{- 3}$
Nearest integer, $x = 64$