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Q. If $80 \,g$ of copper sulphate $CuSO _{4} \cdot 5 H _{2} O$ is dissolved in deionised water to make $5\, L$ of solution. The concentration of the copper sulphate solution is $x \times 10^{-3}\, mol\, L ^{-1}$. The value of $x$ is ____
[Atomic masses $Cu : 63.54 \,u , S : 32\, u , O : 16\, u , H : 1\, u$ ]

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Solution:

Moles of $CuSO _{4} \cdot 5 H _{2} O =\frac{80}{249.54}$
Molarity $=\frac{\frac{80}{249.54}}{5}=64.117 \times 10^{-3}$
Nearest integer, $x=64$