Question

If $7^{\log x}+x^{\log 7}=98$, then ${\log }_{10}\sqrt{x}=$

• A. 1
• B. $\frac{1}{2}$
• C. 2
• D. 0

Answer 1

Answer: (A)

(i) $x^{\log y}={\gamma }^{\log x}$.
(ii) $7^{\log x}=x^{\log 7}$.
(iii) Convert LHS into $7^{\log x}$ (or) $x^{\log 7}$ and solve for $x$.