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  4. If 7 log x+x log 7=98, then log 10 √x=

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Q. If $7^{\log x}+x^{\log 7}=98$, then $\log _{10} \sqrt{x}=$

Logarithm

Solution:

(i) $x^{\log y}=\gamma^{\log x}$.
(ii) $7^{\log x}=x^{\log 7}$.
(iii) Convert LHS into $7^{\log x}$ (or) $x^{\log 7}$ and solve for $x$.