If (3 x % of y)+(x % of 2 y)=14 % of (x+y), then find the value of (1/x)+(1/y).

Question

If (3 x % of y)+(x % of 2 y)=14 % of (x+y), then find the value of (1/x)+(1/y). (A) (1/5) (B) (4/5) (C) (2/3) (D) (3/5)

Tardigrade Admin · Accepted Answer

Given, (3 x % of y)+(x % of 2 y)=15 % of (x+y) (3 x y/100)+(2 x y/100)=(15/100)(x+y) (5 x y/100)=(15/100)(x+y) ⇒ (x+y/x y)=(5/15) × (100/100) ⇒ (1/y)+(1/x)=(2/3)

Q. If $(3 x %$ of $y) + (x %$ of $2 y) = 14%$ of $(x + y)$ , then find the value of $\frac{1}{x} + \frac{1}{y}$ .

$\frac{1}{5}$

$\frac{4}{5}$

$\frac{2}{3}$

$\frac{3}{5}$

Given, $(3 x %$ of $y) + (x %$ of $2 y) = 15%$ of $(x + y)$
$\frac{3 x y}{100} + \frac{2 x y}{100} = \frac{15}{100} (x + y)$
$\frac{5 x y}{100} = \frac{15}{100} (x + y)$
$\Rightarrow \frac{x + y}{x y} = \frac{5}{15} \times \frac{100}{100}$
$\Rightarrow \frac{1}{y} + \frac{1}{x} = \frac{2}{3}$

Q. If (3x% of y)+(x% of 2y)=14% of (x+y), then find the value of x1​+y1​.

51​

54​

32​

53​