If 20 g of CaCO3 is treated with 100 mL of 20% HCl solution, the amount of CO2 produced is

Question

If 20 g of CaCO3 is treated with 100 mL of 20% HCl solution, the amount of CO2 produced is (A) 22.4 L (B) 8.80 g (C) 4.40g (D) 2.24 L

Tardigrade Admin · Accepted Answer

underset100 g CaCO 3+ underset73 g 2 HCl arrow CaCl + underset44 g CO 2+ H 2 O 100 mL of 20 % HCl solution =20 gHCl Here CaCO 3 is the limiting reactant 100 g of CaCO 3 gives 44 gCO 2 20 g C a C O3 text gives (44/100) × 20 =8.80 g of CO 2

Q. If $20 g$ of $C a C O_{3}$ is treated with $100 m L$ of 20% HCl solution, the amount of $C O_{2}$ produced is

22.4 L

8.80 g

4.40g

2.24 L

$100 g C a C O_{3} + 73 g 2 H Cl \to C a Cl + 44 g C O_{2} + H_{2} O$
$100 m L$ of $20% H Cl$ solution $= 20 g H Cl$
Here $C a C O_{3}$ is the limiting reactant
$100 g$ of $C a C O_{3}$ gives $44 g C O_{2}$
$20 g C a C O_{3} gives \frac{44}{100} \times 20$
$= 8.80 g$ of $C O_{2}$

Q. If 20g of CaCO3​ is treated with 100mL of 20% HCl solution, the amount of CO2​ produced is