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  4. If 20 g of CaCO3 is treated with 100 mL of 20% HCl solution, the amount of CO2 produced is

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Q. If $20\, g $ of $CaCO_3$ is treated with $100 \,mL $ of 20% HCl solution, the amount of $CO_2$ produced is

Some Basic Concepts of Chemistry

Solution:

$\underset{100 g }{ CaCO _3}+\underset{73 g }{2 HCl } \rightarrow CaCl +\underset{44 g }{ CO _2}+ H _2 O$
$100 mL$ of $20 \% HCl$ solution $=20 gHCl$
Here $CaCO _3$ is the limiting reactant
$100 g$ of $CaCO _3$ gives $44 gCO _2$
$20 g C a C O_3 \text { gives } \frac{44}{100} \times 20$
$=8.80 g$ of $CO _2$