If 117 g NaCl is dissolved in 1000 g of water the concentration of the solution is said to be:

Question

If 117 g NaCl is dissolved in 1000 g of water the concentration of the solution is said to be: (A) 2 molar (B) 2 molal (C) 1 normal (D) 1 molal

Tardigrade Admin · Accepted Answer

Molality =( text moles of solute / text massof solvent in kg ) =( text mass of solute/molecular weight / text mass of solvent in kg ) Given mass of solute =117 g molecular mass of NaCl =58.5 mass of solvent =1000 g =1 kg molality =(117 / 58.5/1)=2

Q. If $117 g N a Cl$ is dissolved in $1000 g$ of water the concentration of the solution is said to be:

2 molar

2 molal

1 normal

1 molal

Molality $= \frac{moles of solute}{massof solvent in k g}$
$= \frac{mass of solute/molecular weight}{mass of solvent in k g}$
Given mass of solute $= 117 g$
molecular mass of $N a Cl = 58.5$
mass of solvent $= 1000 g = 1 k g$
molality $= \frac{117/58.5}{1} = 2$

Q. If 117gNaCl is dissolved in 1000g of water the concentration of the solution is said to be: