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Tardigrade
Question
Mathematics
If |1 x x2 x x2 1 x2 1 x|=3, then the value of |x3-1 0 x-x4 0 x-x4 x3-1 x-x4 x3-1 0| is
Q. If
∣
∣
1
x
x
2
x
x
2
1
x
2
1
x
∣
∣
=
3
, then the value of
∣
∣
x
3
−
1
0
x
−
x
4
0
x
−
x
4
x
3
−
1
x
−
x
4
x
3
−
1
0
∣
∣
is
183
157
Determinants
Report Error
Answer:
9
Solution:
D
c
=
D
2
=
9
D
c
=
∣
∣
x
3
−
1
0
x
−
x
4
0
x
−
x
4
x
3
−
1
x
−
x
4
x
3
−
1
0
∣
∣