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Q. If $\begin{vmatrix}1 & x & x^{2} \\ x & x^{2} & 1 \\ x^{2} & 1 & x\end{vmatrix}=3$, then the value of $\begin{vmatrix}x^{3}-1 & 0 & x-x^{4} \\ 0 & x-x^{4} & x^{3}-1 \\ x-x^{4} & x^{3}-1 & 0\end{vmatrix}$ is

Determinants

Solution:

$D_{c}=D^{2}=9$
$D_{c}=\begin{vmatrix}x^{3}-1 & 0 & x-x^{4} \\ 0 & x-x^{4} & x^{3}-1 \\ x-x^{4} & x^{3}-1 & 0\end{vmatrix}$