If 0.32 g of an organic compound containing sulphur produces 0.233 g of BaSO 4, then the percentage of sulphur in it is

Question

If 0.32 g of an organic compound containing sulphur produces 0.233 g of BaSO 4, then the percentage of sulphur in it is (A) 10 % (B) 15 % (C) 20 % (D) 25 %

Tardigrade Admin · Accepted Answer

Percentage of sulphur=(32/233) × ( text weight of BaSO 4/ text weight of compound ) × 100 =(32/233) × (0.233/0.32) × 100=10 %

Q. If $0.32 g$ of an organic compound containing sulphur produces $0.233 g$ of $B a S O_{4}$ , then the percentage of sulphur in it is

$10%$

$15%$

$20%$

$25%$

Percentage of sulphur $= \frac{32}{233} \times \frac{weight of B a S O _{4}}{weight of compound} \times 100$

$= \frac{32}{233} \times \frac{0.233}{0.32} \times 100 = 10%$

Q. If 0.32g of an organic compound containing sulphur produces 0.233g of BaSO4​, then the percentage of sulphur in it is

10%

15%

20%

25%