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Q. If $0.32 g$ of an organic compound containing sulphur produces $0.233 g$ of $BaSO _{4}$, then the percentage of sulphur in it is

Organic Chemistry – Some Basic Principles and Techniques

Solution:

Percentage of sulphur$=\frac{32}{233} \times \frac{\text { weight of } BaSO _{4}}{\text { weight of compound }} \times 100 $

$=\frac{32}{233} \times \frac{0.233}{0.32} \times 100=10 \% $