Question

If $0.30$ mol of zinc are added to 0.52 mol of $HCl$, the moles of $H_2$ formed are:

• A. 0.52
• B. 0.30
• C. 0.26
• D. 0.60

Answer 1

Answer: (C)

$Zn+2HCl\to ZnC{l}_2+H_2$

Here: $HCl$ is a limiting reagent

$\therefore$ Moles of $H_2$ produced $=\frac{\text{ moles of }HCl}{2}$

$=\frac{0.52}{2}=0.26$