Question

Identify the cyclic silicate ion given in the figure below,

• A. ${\left[S{i}_4{O}_{25}\right]}^{24-}$
• B. ${\left[S{i}_6{O}_{18}\right]}^{12-}$
• C. ${\left[S{i}_4{O}_{18}\right]}^{12}$
• D. ${\left[S{i}_6{O}_{24}\right]}^{12-}$

Answer 1

Answer: (B)

In cyclic silicate, two oxygen atoms of each tetrahedron are shared to form a ring with general formula ${\left[Si{O}_3\right]}_n^{2n-}$ .
Thus, in the given figure cyclic silicate is${\left[S{i}_6{O}_{18}\right]}^{12-}$