Question

Identify the cyclic silicate ion given in the figure below,

• A. $\left[Si_{4}O_{25}\right]^{24-}$
• B. $\left[Si_{6}O_{18}\right]^{12-}$
• C. $\left[Si_{4}O_{18}\right]^{12}$
• D. $\left[Si_{6}O_{24}\right]^{12-}$

Answer 1

Answer: (B)

In cyclic silicate, two oxygen atoms of each tetrahedron are shared to form a ring with general formula $\left[SiO_{3}\right]^{2n-}_{n}$ .
Thus, in the given figure cyclic silicate is$\left[Si_{6}O_{18}\right]^{12-}$