Question

Identify the correct pathway to convert propanoic acid to ethylamine. The reagent represented by $A$, $B$ and $C$ are
$C{H}_{3}C{H}_{2}COOH\stackrel{A}{\to }X\stackrel{B}{\to }Y\stackrel{C}{\to }C{H}_{3}C{H}_{2}N{H}_2$

	$A$	$B$	$C$
(a)	$Ca(OH{)}_2$	Heat	$Pt/H_2$
(b)	$SOC{l}_2$	$N{H}_3$	$B{r}_2/KOH$
(c)	$HN{O}_2$	$P+I_2$	$LiAl{H}_4$
(d)	$HCN$	$N{H}_3$	$B{r}_2/KOH$

• A. a
• B. b
• C. c
• D. d

Answer 1

Answer: (B)

$C{H}_{3}C{H}_{2}COOH\underset{(A)}{\overset{SOC{l}_2}{\to }}\underset{(X)}{C{H}_{3}C{H}_{2}COCl}\underset{(B)}{\overset{N{H}_3}{\to }}C{H}_{3}C{H}_{2}N{H}_2$
$\underset{(C)}{\overset{B{r}_2/KOH}{\leftarrow }}\underset{(Y)}{C{H}_{3}C{H}_{2}CON{H}_2}$