Question

Identify the correct pathway to convert propanoic acid to ethylamine. The reagent represented by $A$, $B$ and $C$ are
$CH_3CH_2COOH \xrightarrow{A}X \xrightarrow{B}Y \xrightarrow{C}CH_3CH_2NH_2$

	$A$	$B$	$C$
(a)	$Ca(OH)_2$	Heat	$Pt/H_2$
(b)	$SOCl_2$	$NH_3$	$Br_2/KOH$
(c)	$HNO_2$	$P+I_2$	$LiAlH_4$
(d)	$HCN$	$NH_3$	$Br_2/KOH$

• A. a
• B. b
• C. c
• D. d

Answer 1

Answer: (B)

$CH _{3} CH _{2} COOH \xrightarrow[{(A)}]{SOCl_2} \underset{(X)}{CH _{3} CH _{2} COCl} \xrightarrow[{(B)}]{NH _{3}} CH _{3} CH _{2} NH _{2}$
$\xleftarrow[{(C)}]{Br_2/KOH} \underset{(Y)}{CH _{3} CH _{2} CONH _{2}}$