Question

Identify Bronsted-Lowry acids in the reaction given. $\underset{(A)}{{[Al{(H_{2}O)}_2]}^{3+}}+\underset{(B)}{HC{O}_3^{-}}\underset{(C)}{{[Al{(H_{2}O)}_5(O{H}^{-})]}^{2+}}$ $\underset{(D)}{+H_{2}C{O}_3}$ The correct answer is

• A. ,
• B. (B,)
• C. ,
• D. ,

Answer 1

Answer: (C)

According to Bronsted-Lowry, acids are the substance which can donate a proton while bases are the substance which can accept a proton. A base after gaining a proton $(H^{+})$ gives conjugated acid. $\underset{acid}{{[Al{(H_{2}O)}_6]}^{3+}}+\underset{\begin{array}{c}(B)\\ base\end{array}}{HC{O}_3^{-}}\rightleftharpoons$ $\underset{\begin{array}{c}C\\ conjugatebase\end{array}}{{[Al{(H_{2}O)}_5(O{H}^{-})]}^{2+}}+\underset{\begin{array}{c}(D)\\ conjugateacid\end{array}}{H_{2}C{O}_3}$ Hence, in the above reaction A and D are the acids.