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Q. Identify Bronsted-Lowry acids in the reaction given. $ \underset{(A)}{\mathop{{{[Al{{({{H}_{2}}O)}_{2}}]}^{3+}}}}\,+\underset{(B)}{\mathop{HCO_{3}^{-}}}\,\underset{(C)}{\mathop{{{[Al{{({{H}_{2}}O)}_{5}}(O{{H}^{-}})]}^{2+}}}}\, $ $ \underset{(D)}{\mathop{+{{H}_{2}}C{{O}_{3}}}}\, $ The correct answer is

EAMCETEAMCET 2008

Solution:

According to Bronsted-Lowry, acids are the substance which can donate a proton while bases are the substance which can accept a proton. A base after gaining a proton $ ({{H}^{+}}) $ gives conjugated acid. $ \underset{acid}{\mathop{{{[Al{{({{H}_{2}}O)}_{6}}]}^{3+}}}}\,+\underset{\begin{smallmatrix} (B) \\ base \end{smallmatrix}}{\mathop{HCO_{3}^{-}}}\,\rightleftharpoons $ $ \underset{\begin{smallmatrix} \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C \\ conjugate\,base \end{smallmatrix}}{\mathop{{{[Al{{({{H}_{2}}O)}_{5}}(O{{H}^{-}})]}^{2+}}}}\,+\underset{\begin{smallmatrix} \,\,\,\,\,\,\,\,\,\,\,\,\,(D) \\ conjugate\,acid \end{smallmatrix}}{\mathop{{{H}_{2}}C{{O}_{3}}}}\, $ Hence, in the above reaction A and D are the acids.