Ice point and steam point on a particular scale reads 10° and 80° respectively. The temperature on ° F scale when temperature on new scale is 45° is

Question

Ice point and steam point on a particular scale reads 10° and 80° respectively. The temperature on ° F scale when temperature on new scale is 45° is (A) 50 oF (B) 112oF (C) 122 oF (D) 138 oF

Tardigrade Admin · Accepted Answer

Relation between the two scales (t - 10/80 - 10)=(F - 32/212 - 32) F-32=(18/7)(t - 10) F=(18/7)(45 - 10)+32 F=122 oF

Q. Ice point and steam point on a particular scale reads $1 0^{\circ}$ and $8 0^{\circ}$ respectively. The temperature on $^{\circ} F$ scale when temperature on new scale is $4 5^{\circ}$ is

$5 0^{o} F$

$11 2^{o} F$

$12 2^{o} F$

$138^{o} F$

Relation between the two scales
$\frac{t - 10}{80 - 10} = \frac{F - 32}{212 - 32}$
$F - 32 = \frac{18}{7} (t - 10)$
$F = \frac{18}{7} (45 - 10) + 32$
$F = 12 2^{o} F$

Q. Ice point and steam point on a particular scale reads 10∘ and 80∘ respectively. The temperature on ∘F scale when temperature on new scale is 45∘ is

50oF

112oF

122oF

138oF