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Q. Ice point and steam point on a particular scale reads $10^\circ $ and $80^\circ $ respectively. The temperature on $^\circ F$ scale when temperature on new scale is $45^\circ $ is

NTA AbhyasNTA Abhyas 2020Thermal Properties of Matter

Solution:

Relation between the two scales
$\frac{t - 10}{80 - 10}=\frac{F - 32}{212 - 32}$
$F-32=\frac{18}{7}\left(t - 10\right)$
$F=\frac{18}{7}\left(45 - 10\right)+32$
$F=122^{ \, o}F$