Hydrogen reacts with nitrogen to form ammonia as, N2(g)+3H2(g) arrow 2NH3(g) The amount of ammonia that would be produced if 200.0 g of H2 reacts is

Question

Hydrogen reacts with nitrogen to form ammonia as, N2(g)+3H2(g) arrow 2NH3(g) The amount of ammonia that would be produced if 200.0 g of H2 reacts is (A) 1133.3 g (B) 11333 g (C) 1032.2 g (D) 8692.6 g

Tardigrade Admin · Accepted Answer

N2+3H2 arrow 2NH3, 6 g H2=34 g of NH3 ∴ 200 g H2=(34/6)×200=1133.3 g

Q. Hydrogen reacts with nitrogen to form ammonia as, $N_{2 (g)} + 3 H_{2 (g)} \to 2 N H_{3 (g)}$
The amount of ammonia that would be produced if 200.0 g of $H_{2}$ reacts is

1133.3 g

11333 g

1032.2 g

8692.6 g

$N_{2} + 3 H_{2} \to 2 N H_{3}, 6 g H_{2} = 34 g o f N H_{3}$
$∴ 200 g H_{2} = \frac{34}{6} \times 200 = 1133.3 g$

Q. Hydrogen reacts with nitrogen to form ammonia as, N2(g)​+3H2(g)​→2NH3(g)​ The amount of ammonia that would be produced if 200.0 g of H2​ reacts is