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  4. Hydrogen reacts with nitrogen to form ammonia as, N2(g)+3H2(g) arrow 2NH3(g) The amount of ammonia that would be produced if 200.0 g of H2 reacts is

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Q. Hydrogen reacts with nitrogen to form ammonia as, $N_{2\left(g\right)}+3H_{2\left(g\right)} \rightarrow 2NH_{3\left(g\right)}$
The amount of ammonia that would be produced if 200.0 g of $H_2$ reacts is

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Solution:

$N_{2}+3H_{2} \rightarrow 2NH_{3}, 6\,g\,H_{2}=34\,g\,of \, NH_{3}$
$\therefore 200\,g\,H_{2}=\frac{34}{6}\times200=1133.3\,g$