Hydrogen and helium volume V at same temperature T and same pressure p are mixed to have same volume V. The resulting pressure of the mixture will be

Question

Hydrogen and helium volume V at same temperature T and same pressure p are mixed to have same volume V. The resulting pressure of the mixture will be (A)  (R/2)  (B) P (C) 2P (D) depending on the relative mass of the gases

Tardigrade Admin · Accepted Answer

From ideal gas equation, we have pV = RT When two gases are mixed, then pV+pV=p'V ⇒ p'=2p Hence, resultant pressure will be doubled.

Q. Hydrogen and helium volume $V$ at same temperature $T$ and same pressure $p$ are mixed to have same volume $V$ . The resulting pressure of the mixture will be

$\frac{R}{2}$

$P$

$2 P$

depending on the relative mass of the gases

From ideal gas equation, we have
$p V = RT$
When two gases are mixed, then
$p V + p V = p^{'} V$
$\Rightarrow$ $p^{'} = 2 p$
Hence, resultant pressure will be doubled.

Q. Hydrogen and helium volume V at same temperature T and same pressure p are mixed to have same volume V. The resulting pressure of the mixture will be

2R​

P

2P

depending on the relative mass of the gases

From ideal gas equation, we have pV=RT When two gases are mixed, then pV+pV=p′V ⇒ p′=2p Hence, resultant pressure will be doubled.

Q. Hydrogen and helium volume $V$ at same temperature $T$ and same pressure $p$ are mixed to have same volume $V$ . The resulting pressure of the mixture will be

$\frac{R}{2}$

$P$

$2 P$

From ideal gas equation, we have
$p V = RT$
When two gases are mixed, then
$p V + p V = p^{'} V$
$\Rightarrow$ $p^{'} = 2 p$
Hence, resultant pressure will be doubled.