Hydrazene can be used in fuel cell N 2 H 4( aq )+ O 2( g ) longrightarrow N 2( g )+2 H 2 O (ℓ). If Δ G ° for this reaction is -600 kJ, what will be the E ° for the cell?

Question

Hydrazene can be used in fuel cell N 2 H 4( aq )+ O 2( g ) longrightarrow N 2( g )+2 H 2 O (ℓ). If Δ G ° for this reaction is -600 kJ, what will be the E ° for the cell? (A) 1.25 V (B) 1.50 V (C) 1.57 V (D) 1.75 V

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/6d21fda6675deda0225cde9c2a9fb241-.png" /> Δ G °=- nFE °=-4 × 96500 × E ° -600 × 103=-4 × 96500 × E ° E °=(-600 × 103/-4 × 96500) ⇒ 1.55 V

Q. Hydrazene can be used in fuel cell $N_{2} H_{4 (a q)} + O_{2 (g)} ⟶ N_{2 (g)} + 2 H_{2} O_{(ℓ)}$ . If $Δ G^{\circ}$ for this reaction is $- 600 k J$ , what will be the $E^{\circ}$ for the cell?

1.25 V

1.50 V

1.57 V

1.75 V

$Δ G^{\circ} = - n F E^{\circ} = - 4 \times 96500 \times E^{\circ}$
$- 600 \times 1 0^{3} = - 4 \times 96500 \times E^{\circ}$
$E^{\circ} = \frac{- 600 \times 1 0 ^{3}}{- 4 \times 96500} \Rightarrow 1.55 V$

Q. Hydrazene can be used in fuel cell N2​H4(aq)​+O2(g)​⟶N2(g)​+2H2​O(ℓ)​. If ΔG∘ for this reaction is −600kJ, what will be the E∘ for the cell?