Question

Hydrazene can be used in fuel cell $N _{2} H _{4( aq )}+ O _{2( g )} \longrightarrow N _{2( g )}+2 H _{2} O _{(\ell)}$. If $\Delta G ^{\circ}$ for this reaction is $-600\, kJ$, what will be the $E ^{\circ}$ for the cell?

• A. 1.25 V
• B. 1.50 V
• C. 1.57 V
• D. 1.75 V

Answer 1

Answer: (C)

$\Delta G ^{\circ}=- nFE ^{\circ}=-4 \times 96500 \times E ^{\circ}$
$-600 \times 10^{3}=-4 \times 96500 \times E ^{\circ}$
$E ^{\circ}=\frac{-600 \times 10^{3}}{-4 \times 96500} \Rightarrow 1.55\, V$