Hybridization of [ Ni ( CO )4] is

Question

Hybridization of [ Ni ( CO )4] is (A) sp 3 (B) d 2 sp 3 (C) sp 3 d (D) sp 2

Tardigrade Admin · Accepted Answer

In the compound [ Ni ( CO )4] Oxidation number of Ni =0 Co-ordination number of Ni =4 (CO (carbonyl) is a strong ligand so it cause pairing of electron) <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/91afe378e04e17cc730275e79c0f2e7d-.png" />

Q. Hybridization of $[N i (CO)_{4}]$ is

$s p^{3}$

$d^{2} s p^{3}$

$s p^{3} d$

$s p^{2}$

In the compound $[N i (CO)_{4}]$

Oxidation number of $N i = 0$

Co-ordination number of $N i = 4$

(CO (carbonyl) is a strong ligand so it cause pairing of electron)

Q. Hybridization of [Ni(CO)4​] is

sp3

d2sp3

sp3d

sp2