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  4. Hybridization of [ Ni ( CO )4] is

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Q. Hybridization of $\left[ Ni ( CO )_{4}\right]$ is

The d-and f-Block Elements

Solution:

In the compound $\left[ Ni ( CO )_{4}\right]$

Oxidation number of $Ni =0$

Co-ordination number of $Ni =4$

(CO (carbonyl) is a strong ligand so it cause pairing of electron)

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