Question

Hybridisation of $Fe$ in $K_3[Fe{(CN)}_6]$ is

• A. $s{p}^3$
• B. $d^{2}s{p}^3$
• C. $s{p}^3{d}^2$
• D. $ds{p}^3$

Answer 1

Answer: (B)

$F{e}^{3+}:[Ar]3d^5$ Number of ligand = 6 Nature of ligand is strong field. $F{e}^{3+}:$
${[Fe{(CN)}_6]}^{3-}:$
Hence, hybridization of Fe is $d^{2}s{p}^3$ .