Question

Hybridisation of $ Fe $ in $ {{K}_{3}}[Fe{{(CN)}_{6}}] $ is

• A. $ s{{p}^{3}} $
• B. $ {{d}^{2}}s{{p}^{3}} $
• C. $ s{{p}^{3}}{{d}^{2}} $
• D. $ ds{{p}^{3}} $

Answer 1

Answer: (B)

$ F{{e}^{3+}}:[Ar]3{{d}^{5}} $ Number of ligand = 6 Nature of ligand is strong field. $ F{{e}^{3+}}: $
$ {{[Fe{{(CN)}_{6}}]}^{3-}}: $
Hence, hybridization of Fe is $ {{d}^{2}}s{{p}^{3}} $ .