How much methyl alcohol should be mixed with 10 litre water so that it freezes at - 6° C ? (Molal depression constant for water = 1.86, molecular weight of methyl alcohol =32)

Question

How much methyl alcohol should be mixed with 10 litre water so that it freezes at - 6° C ? (Molal depression constant for water = 1.86, molecular weight of methyl alcohol =32) (A) 1.03 × 103 gram (B) 1.03 × 102 gram (C) 1.26 × 103 gram (D) 106 gram.

Tardigrade Admin · Accepted Answer

Correct answer is (a) 1.03 × 103 gram

Q. How much methyl alcohol should be mixed with $10$ litre water so that it freezes at - $6^{\circ} C$ ? (Molal depression constant for water $= 1.86$ , molecular weight of methyl alcohol $= 32$ )

$1.03 \times 1 0^{3}$ gram

$1.03 \times 1 0^{2}$ gram

$1.26 \times 1 0^{3}$ gram

$106$ gram.

Correct answer is (a) $1.03 \times 1 0^{3}$ gram

Q. How much methyl alcohol should be mixed with 10 litre water so that it freezes at - 6∘C ? (Molal depression constant for water =1.86, molecular weight of methyl alcohol =32)

1.03×103 gram

1.03×102 gram

1.26×103 gram

106 gram.