Question

How much methyl alcohol should be mixed with $10$ litre water so that it freezes at - $6^{\circ} C$ ? (Molal depression constant for water $= 1.86$, molecular weight of methyl alcohol $=32$)

• A. $1.03 \times 10^3$ gram
• B. $1.03 \times 10^2$ gram
• C. $1.26 \times 10^3$ gram
• D. $106$ gram.

Answer 1

Answer: (A)

Correct answer is (a) $1.03 \times 10^3$ gram