How much metal will be deposited when a current of 12 ampere with 75 % efficiency is passed through the cell for 3 h ? (Given: Z = 4 × 10-4)

Question

How much metal will be deposited when a current of 12 ampere with 75 % efficiency is passed through the cell for 3 h ? (Given: Z = 4 × 10-4) (A) 32.4 g (B) 38. 8 g (C) 36.0 g (D) 22.4 g

Tardigrade Admin · Accepted Answer

W=Z× I× t =4×10-4×12×(75/100)× 3× 3600 =38.8 g

Q. How much metal will be deposited when a current of $12$ ampere with $75%$ efficiency is passed through the cell for $3 h$ ? (Given : $Z = 4 \times 1 0^{- 4}$ )

$32.4 g$

$38.8 g$

$36.0 g$

$22.4 g$

$W = Z \times I \times t$
$= 4 \times 1 0^{- 4} \times 12 \times \frac{75}{100} \times 3 \times 3600$
$= 38.8 g$

Q. How much metal will be deposited when a current of 12 ampere with 75% efficiency is passed through the cell for 3h ? (Given : Z=4×10−4)

32.4g

38.8g

36.0g

22.4g