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Q. How much metal will be deposited when a current of $12$ ampere with $75\%$ efficiency is passed through the cell for $3 \,h$ ? (Given : $Z = 4 \times 10^{-4}$)

Electrochemistry

Solution:

$W=Z\times I\times t$
$=4\times10^{-4}\times12\times\frac{75}{100}\times 3\times 3600$
$=38.8\,g$