How much electric flux will come out through a surface 5=10 hatj kept in an electrostatic field overset arrow E=2 hati+4 hatj+7 hatk

Question

How much electric flux will come out through a surface 5=10 hatj kept in an electrostatic field overset arrow E=2 hati+4 hatj+7 hatk (A) 20units (B) 40units (C) 70units (D) nearly 80 units

Tardigrade Admin · Accepted Answer

φ= overset arrow E⋅ overset arrow S =(.2 hati+4 hatj+7 hatk.)⋅ 10j=40units

Q. How much electric flux will come out through a surface $5 = 10 \hat{j}$ kept in an electrostatic field $E \to = 2 \hat{i} + 4 \hat{j} + 7 \hat{k}$

$20 u ni t s$

$40 u ni t s$

$70 u ni t s$

nearly $80$ units

$ϕ = E \to \cdot S \to = (2 \hat{i} + 4 \hat{j} + 7 \hat{k}) \cdot 10 j = 40 u ni t s$

Q. How much electric flux will come out through a surface 5=10j^​ kept in an electrostatic field E→=2i^+4j^​+7k^

20units

40units

70units

nearly 80 units