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  4. How much electric flux will come out through a surface 5=10 hatj kept in an electrostatic field overset arrow E=2 hati+4 hatj+7 hatk

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Q. How much electric flux will come out through a surface $5=10\hat{j}$ kept in an electrostatic field $\overset{ \rightarrow }{E}=2\hat{i}+4\hat{j}+7\hat{k}$

NTA AbhyasNTA Abhyas 2020

Solution:

$\phi=\overset{ \rightarrow }{E}\cdot \overset{ \rightarrow }{S} \\ =\left(\right.2\hat{i}+4\hat{j}+7\hat{k}\left.\right)\cdot 10j=40units$